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15问答网 > 铜与浓硝酸反应的化学方程式如下：Cu+4HNO3（浓）═Cu（NO3）2+2NO2↑+2H2O将 3.2g铜完全溶于足量的 50mL

铜与浓硝酸反应的化学方程式如下：Cu+4HNO3（浓）═Cu（NO3）2+2NO2↑+2H2O将 3.2g铜完全溶于足量的 50mL

2025-03-14 03:36:45

推荐回答（1个）

回答1：

（1）3.2g铜的物质的量为

3.2g

64g/mol

=0.05mol，则：
   Cu+4HNO₃（浓）═Cu（NO₃）₂+2NO₂↑+2H₂O
   1                         2
0.05mol                     0.1mol
故NO₂的体积为：0.1mol×22.4L/mol=2.24L，
答：生成的NO₂的体积为2.24L；
（2）50mL 11.0mol?L^-1 的浓硝酸中n（HNO₃）=0.05L×11.0mol?L^-1=0.55mol，
故反应后溶液中n（NO₃^-）=n_原（HNO₃）-n（NO₂）=0.55mol-0.1mol=0.45mol，
故反应后溶液中c（NO₃^-）=

0.45mol

0.05L

=9mol/L，
故答案为：9mol/L．

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