求摆线x=t-sint,y=1-cost,在0度<=t<=360度上的弧线与直线y=3⼀2的交点。空间解析几何

2025-03-20 06:43:55
推荐回答(1个)
回答1:

y=1-cost=3/2 ==>cost=-1/2.
0<=t<=2Pi ==>t=5Pi/6,sint=sqrt(3)/2 or t=7Pi/6,sint=-sqrt(3)/2.
==>x=5Pi/6-sqrt(3)/2 or x=7Pi/6+sqrt(3)/2.
交点为(5Pi/6-sqrt(3)/2,3/2)或(7Pi/6+sqrt(3)/2,3/2).