在高数教材(同济版)中,定义x趋于x0函数极限为什么去掉x0点?复合函数的极限也强调该问题,去了会会怎样

2025-03-28 21:05:01
推荐回答(2个)
回答1:

因为在有些情况下,函数在x=x0点无意义,比如f(x)=(x-1)/(x+1),当x=-1时函数无意义,也就是不存在f(-1),而只能用求极限的方式求f(x)limx趋于(-1)

对于f(x)=(x-1)/(x+1)一类函数,x=-1是必须去掉的,因为它本身不存在。

而对于连续函数,临时抽调只是思辨上的一种方法,而通过论证,客观上是去不掉的,就是当x从“x0-”和“x0+”趋于x0时,其极限值都等于f(x0),这就是连续函数与非连续函数的区别。

回答2:

函数x趋于0的问题,我们只关心它在0点附近的取值情况,与它在0点的值没有任何关系,甚至可能在0点没有定义。
比如极限:sin(x)/x 在 x趋于0时极限为1,但分母上的x在0点没有定义,我们只要考虑零点附近的函数值。

上面那人的回答跟题意无关,这跟连续函数没有关系,仅仅是函数极限的概念。

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