解方程(组).(1)2x+13-10x+16=1(2)x?y=32y+3(x?y)=1

解方程(组).(1)2x+13-10x+16=1(2)x?y=32y+3(x?y)=11
2025-04-14 19:45:26
推荐回答(1个)
回答1:

(1)去分母、去括号得,4x+2-10x-1=6,
移项、合并同类项得,-6x=5,
系数化为1得x=-

5
6


(2)整理方程组,得
x?y=3
3x?y=11

②-①,得2x=8,
∴x=4,
把x=4代入①,得y=1,
∴原方程组的解为
x=4
y=1