-2t的平方+4t+4⼀t的平方-2t-1<0 怎么解?

2025-03-19 07:34:38
推荐回答(1个)
回答1:

(-2t^2+4t+4)/(t^2-2t-1)<0,
<==>(t^2-2t-2)/(t^2-2t-1)>0,
<==>(t-1+√3)(t-1-√3)(t-1+√2)(t-1-√2)>0,
由序轴标根法,t<1-√3,或1-√21+√3,为所求.