(1)R1、R2串联时,通过两电阻的电流相等,
∵P=I2R,且P2=3P1,
∴R2=3R1,
∵U=IR,
∴U1:U2=R1:R2=1:3;
电路中的电流I=
=U
R1+R2
=U
R1+3R1
,U 4R1
则P1=I2R1=(
)2R1=U 4R1
.U2 16R1
(2)当R1、R2并联在同一电源两端时,两电阻两端的电压相等为U,
R1消耗的功率为P1′=
=16P1;U2 R1
∵I=
,U R
∴通过R1与R2的电流之比I1′:I2′=R2:R1=3:1;
电路消耗的总功率P总′=
+U2 R1
=U2 R2
+U2 R1
=U2 3R1
×16P1=4 3
P1.64 3
故选B.