求极限:x→0时,(x-sinxcosx)⼀x대

2025-03-24 15:31:27
推荐回答(1个)
回答1:

x->0

sin2x = 2x -(1/6)(2x)^3 +o(x^3) = 2x- (4/3)x^3 +o(x^3)

x-(1/2)sin2x = (2/3)x^3 +o(x^3)

lim(x->0) ( x- sinx.cosx) /x^3

=lim(x->0) [ x-  (1/2)sin2x ] /x^3

=lim(x->0) (2/3)x^3  /x^3

=2/3