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15问答网 > 信道带宽为3KHz,信噪比为1023,则每秒能发送的比特数不会超过多少?

信道带宽为3KHz,信噪比为1023,则每秒能发送的比特数不会超过多少?

2025-04-03 23:54:10

推荐回答（1个）

回答1：

题目应该问：每秒能正确发送的比特数不会超过多少？
如果你不管接受端正确与否，每秒你想发多少就能发多少。

这个是考你香农信道容量公式，C=B*log2(1+S/N)
S/N就是信噪比
把已知条件带入就能算的信道容量C
每秒能发送的比特数不会超过这个C。

香农公式见百度百科
http://baike.baidu.com/view/747964.htm

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