推荐回答(5个)
一楼你傻的啊,第一次的时候,a回,那还不会被吃掉啊,二楼的更傻,人家楼主都说了,两只大老虎会沉船,你还要BC一起过,呵呵。
还是我来:
按照道理来说这题是无解的,因为无任哪一次最多只能过一只大老虎,所以无法造成三个大老虎在一边的情况,最多只能造成对岸一对母子,另一边两对母子,这样一来,无任怎么去接都不能完成任务,所以说应该无解。但是还有这样的可能,当然这只是可能:
一、Aa先过,A让a先走,在一个地方等A,然后,A过去把Bb换过来,然后B把b藏起来,再B把A换过来,A跟a走了,再b出来,过河把Cc换过来,C让c先走,在一个地方等C,然后,C过去把Bb换过来,等Bb走了,c再过去把C接过来,呵呵,其实我认为这种不好,至少没有下面那种好!
二、这种了就要讲亲情了,虎毒不食子,同样也不可能看着自己的儿子被吃不是,所以就有这样的过法。
(1)、Ab过 (A警告B,如果他送船回的时候,在要靠岸的时候如果没有看到a,那他就返回去把b也吃掉,所以,B就会保护a)
(2)、A回,再ac过
(3)、a回,再A过 (同样的道理,因为对岸还有bc,下次A会让b过去把a接回来,如果在还没有靠岸的船上看不到a,那就把c吃掉,所以C就会保护a) 这时对岸有Abc
(4)、b回,再Ba过 (道理不用再讲了吧) 这时对岸有ABac
(5)、a回,再Cb过
(6)、最后A过去把a接过河
呵呵,这样还行吧
大老虎为ABC,相应的小老虎为abc,其中c会划船。
1、ac过河,c回来 (a小老虎已过河)
2、bc过河,c回来 (ab小老虎已过河)
3、BA过河,Bb回来 (Aa母子已过河)
4、Cc过河,Aa回来 (Cc母子已过河)
5、AB过河,c回来 (ABC三个大老虎已过河)
6、ca过河,c回来 (ABCa已过河)
7、cb过河,大功告成
Ab过
A回,再ac过
(a回,再A过 这时对岸有Abc
b回,再Ba过 这时对岸有ABac
a回,再Cb过
最后A过去把a接过河
先Aa去a回,再ab去b回,再Bb去b回,再bc去c回,最后Cc去。
ab去a回,
ac去a回,
BC去Bb回,
AB去c回,
ab去a回,
ac去。
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