已知log以2为底的3=a log以3为底的7=b 试用a.b表示log以12为底的56

2025-01-19 02:36:10
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回答1:

log2(3)=a, log3(7)=b.

log12(56)=log3(7*8)=log3(7)+3log3(2)
=b+3[log2(2)/log2(3)]
=b(1/a)=b/a