C语言文件中字符串的查找与替换

2025-02-06 17:09:39
推荐回答(5个)
回答1:

  #include
  #include
  #include
  #include
  void Substitute(char *pInput, char *pOutput, char *pSrc, char *pDst)
  {
  char    *pi, *po, *p;
  int     nSrcLen, nDstLen, nLen;
  // 指向输入字符串的游动指针.
  pi = pInput;
  // 指向输出字符串的游动指针.
  po = pOutput;
  // 计算被替换串和替换串的长度.
  nSrcLen = strlen(pSrc);
  nDstLen = strlen(pDst);
  // 查找pi指向字符串中第一次出现替换串的位置,并返回指针(找不到则返回null).
  p = strstr(pi, pSrc);
  if(p)
  {
  // 找到.
  while(p)
  {
  //计算被替换串前边字符串的长度.
  nLen = (int)(p - pi);
  // 复制到输出字符串.
  memcpy(po, pi, nLen);
  memcpy(po + nLen, pDst, nDstLen);
  // 跳过被替换串.
  pi = p + nSrcLen;
  // 调整指向输出串的指针位置.
  po = po + nLen + nDstLen;
  // 继续查找.
  p = strstr(pi, pSrc);
  }
  // 复制剩余字符串.
  strcpy(po, pi);
  }
  else
  {
  // 没有找到则原样复制.
  strcpy(po, pi);
  }
  }
  int main(int ac, char *av[])
  {
  if (ac!=5) {
  printf("程序名 要操作的文件 新文件 查找的字符串 替换的字符串\n");
  printf("示例:test.exe 1.txt 2.txt hello love\n");
  return 0;
  }
  const int MAXSIZES = 100;
  FILE *fpSrc,*fpDes;
  char filename1[20]="1.txt";
  char filename2[20]="2.txt";
  //要求查找的字符串,替换的字符串;
  char ps[]="hello";
  char pd[]="love";
  //求取所查找和替换的字符串的长度;
  int len_src=strlen(av[3]);
  int len_des=strlen(av[4]);
  //定义存储字符串缓冲区;很奇怪的一点是,fgets函数不能将字符串写入动态分配的内存中
  /*char* Src_buf=(char*)(sizeof(char)*MAXSIZES);
  char* Cpy_buf=(char*)(sizeof(char)*MAXSIZES);
  char* Des_buf=(char*)(sizeof(char)*MAXSIZES);*/
  char Src_buf[MAXSIZES] = {0};
  char Cpy_buf[MAXSIZES] = {0};
  char Des_buf[MAXSIZES] = {0};
  //打开文件
  if((fpSrc=fopen(av[1],"r+"))==NULL)
  {
  printf("fail to open the file1 !\n");
  exit(1);
  }
  if((fpDes=fopen(av[2],"a+"))==NULL)
  {
  printf("fail to open the file2 !\n");
  exit(1);
  }
  //进行循环读取
  while(!feof(fpSrc))//判断文件是否已结束;!feof(fpSrc)
  {
  fgets(Src_buf,MAXSIZES,fpSrc);
  Substitute(Src_buf,Des_buf,av[3],av[4]);
  fputs(Des_buf,fpDes);
  printf("%s",Des_buf);
  }
  fclose(fpSrc);
  fclose(fpDes);
  system("pause");
  return 0;
  }

说明:使用c标准为中的文件I/O函数一般是不推荐的,做为练习可以学习,真正用的最多的是内存文件映射。那要比用I/O函数读来读取方便的多,限制也会更小。

回答2:

用"rb" open, 用 fread 读, 用 fwrite 写.
记录地点 用 fgetpos.

下面程序例子是按你的原来题意,找目标字串,输出用替代字.直接用文件操作,不开单元存放文件.

输入文件 a.txt 输出文件 tmp.txt

至于你的新要求,给你提示记录地点的方法.你可以rewind(fin),从头一个字一个字读,读一个输出一个,读到的位置等于POS[i]-80时,读80个字但不输出,这就去掉了80个字.
例如找到的POS[]共NN个。
#define buff_size 1024
long int n,n1,n2,i,j,k;
char *buff;
buff=(char*) malloc(buff_size * sizeof(char));
rewind(fin);
for(k=0;kif (k==0) {n=POS[k]-80;} else {n=POS[k]-POS[k-1]-80;};
n1 = n / buff_size; n2 = n % buff_size;
if (n1 >0) for (i=0;ifread(buff,sizeof(char),buff_size,fin);
fwrite(buff,sizeof(char),buff_size,fout);
};
if (n2 > 0) {fread(buff,sizeof(char),n2,fin);
fwrite(buff,sizeof(char),n2,fout);
};
fread(buff,sizeof(char),80,fin);
for (i=0;i<80;i++) buff[i]='0'; buff[80]='\0';
fwrite(buff,sizeof(char),80,fout);
} ; end for k
这里请自己写 读最后一段,无需改零,读一个字,输出一个字,直到EOF.
-----------------
#include
#include

void main (int argc, char *argv[])
{
FILE *fin,*fout;
char namein[72]="a.txt";
char nameout[72]="tmp.txt";
char target[120],tidai[120];
char work[120];
int L1,L2,i,k=0;
int numread;
fpos_t pos;
fpos_t POS[100];

printf("Enter target string: ");
scanf("%s",&target[0]);
L1 = strlen(target);
printf("Enter replace string: ");
scanf("%s",&tidai[0]);
L2 = strlen(tidai);

if ( (fin = fopen(namein,"rb") ) == NULL ) {
printf("\007Cann't open input file: %s ", namein);exit(1);
};

if ( (fout = fopen(nameout,"wb") ) == NULL ) {
printf("\007Cann't open temp work file: %s ", nameout);exit(1);
};

Lab1:
numread = fread( work, sizeof( char ), L1, fin );
if (numread < L1) {
// fwrite( work, sizeof( char ), numread, fout );
goto done;
};
if ( strncmp(work,target,L1) == 0 ){
// fwrite( tidai, sizeof( char ), L2, fout );
if( fgetpos( fin, &pos ) != 0 ) perror( "fgetpos error" );
else { POS[k] = pos-L1; k=k+1;};

goto Lab1;
};

Lab2:
// fwrite( &work[0], sizeof( char ), 1, fout );
for (i=0;ifread( &work[L1-1], sizeof( char ), 1, fin );
if (feof(fin)) {
// fwrite( &work[1], sizeof( char ), L1-1, fout );
goto done;
};
if ( strncmp(work,target,L1) == 0 ){
// fwrite( tidai, sizeof( char ), L2, fout );
if( fgetpos( fin, &pos ) != 0 ) perror( "fgetpos error" );
else { POS[k] = pos-L1; k=k+1;};
goto Lab1;
} else {goto Lab2;};

// 新述 rewind(fin); 那部分程序语句插在这里,声明放前面

done: fclose(fin);fclose(fout);
printf("output in %s\n",nameout);
for (i=0;iprintf("%ld \n",(long int) POS[i]);
}
exit(0);
}

回答3:

你可以这样写,void replace() /*替换单词*/
{
char word[max],reword[max],ch;/*word 为被替换单词,reword为替换单词*/
printf("\n======单词替换======\n");
printf("\n请输入欲被替换的单词:");
scanf("%s",&word);
printf("\n共找到%2d 处 ” %s ” \n",wordfind(word),word);
if (!wordfind(word))
{
printf("\n对不起!不存在该单词!");
getchar();
}
else
{
printf("\n该单词替换为:");
scanf("%s",&reword);
printf("\n确定是否要替换为 “ %s ”?(Y/N) : ",reword);
getchar();
scanf("%c",&ch);
if (ch=='y'||ch=='Y')
if (!revisal(pos,strlen(word),reword))
printf("\n修改成功!");
}
}

int wordfind(char word[]) /*单词匹配*/
{
int i=0,s=0,j,k,len,count=0;
char str[max];
len=strlen(psg);
while (i {
if ((psg[i]>='a'&&psg[i]<='z')||(psg[i]>='A'&&psg[i]<='Z'))
{
k=0;
for (j=i;j {
if ((psg[j]>='a'&&psg[j]<='z')||(psg[j]>='A'&&psg[j]<='Z'))
{
str[k]=psg[j]; /*str记录文段中出现的单词*/
k++;
}
else
{
i=j+1;
break;
}
}
if (!strcmp(str,word)) /*对文段中单词和欲替换单词比较*/
{
count++; /*若相同,则统计该单词并记录其起始位置*/
pos[s]=i-k-1;
s++;
}
for (j=0;j str[j]='\0'; /*初始化字符串str*/
}
else
i++;
}
return count;
}

int revisal(int pos[],int len,char reword[]) /*替换后修改文件*/
{
int i=0,j=0,k;
if ((fp=fopen(filename,"w"))==NULL) /*打开文件*/
{
printf("文件打开失败!");
exit(0);
}
while (i {
if (pos[j]==i) /*在文件中修改替换单词*/
{
for (k=0;k fwrite(&reword[k],sizeof(char),1,fp);
i+=len; /*在psg数组中跳过被替换单词*/
j++;
}
else
{
fwrite(&psg[i],sizeof(char),1,fp);
i++;
}
}
if (fclose(fp)) /*关闭文件*/
{
printf("关闭文件失败");
exit(0);
}
getchar();
return 0;
}

回答4:

#include
#include
#include
#include
using namespace std;

int Count=0;

/*
*函数名:findNum
*作者:anglecloudy
*描述:如果存在则返回字符串所在的位置,否则返回0,暂不支持文本中存在多个相同的串
* 先用test.txt文本测试,所有的文本操作都是一样的,不管你怎么命名
*/
int findNum(char *str)
{
FILE *p;
if((p=fopen("test.txt","rb"))==NULL)
{
printf("\n打开文件失败\n");
return 0;
}
char buffer[0x1000]; //保存文件
memset(buffer,0,0x1000); //初始化缓存
size_t fileLen=fread(buffer,sizeof(char),0x1000,p); //得到文件内容,
int readLen=strlen(str);
int IsFind=0;

for(int i=0;i{
if(strncmp(buffer+i,str,readLen)==0)
{
IsFind=i;
}
}

fclose(p);
return IsFind;
}

int main(void)
{
char *str1="1234567";
int t1=0,t2=0;
if((t1=findNum(str1))==0)
{
printf("没有找到字符串%s\n请按任意键退出\n",str1);
return -1;
}
else
{
printf("字符串%s的位置在%d\n",str1,t1);
}
return 0;
}

我只是简单的改了一下你的字符串查找这个函数,其它的没写。主要是你的思想不对,对文件的操作一般先定义一个数组,把文件保存起来,然后再操作,多去http://community.csdn.net上面问问,高手多,下班了。88

回答5:

给些建议:
1.你需要替换的文件是否很大,如果不大(不超过10M),一次读完它,别一个字节一个字节读,自己给自己找麻烦。(获取文件大小/c里面可以用fseek+ftell获取,然后malloc对应大小的空间,一次fread读完。)
理由:你这个不是要长时间运行的系统,不用考虑内存占用,因为跑完就结束了。

2.如果都在内存里了,直接可以用库函数strstr来查找,比你自己比较方便许多,代码也没这么复杂。

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