计算(1)(-2xy2)2?3x2y÷(-x3y4)(2)(2x+y)(2 x-3)-2 y( x-1)(3)3(m+1)2-5(m+1)(m-1

2024-11-23 00:59:20
推荐回答(1个)
回答1:

(1)原式=-22x2y4?3x2y÷x3y4
=-12x4y5÷x3y4
=-12xy
(2)原式=4x2-6x+2xy-3y-2xy+2y
=4x2-6x-y
(3)原式=3(m2+2m+1)-5(m2-1)+2(m2-2m+1)
=3m2+6m+3-5m2+5+2m2-4m+2
=2m+10
(4)原式=-(2x2y-x3y2-

1
2
xy3)×2x-1y-1
=-2x2y×2x-1y-1+x3y2×2x-1y-1+
1
2
xy3
×2x-1y-1
=-4x+2x2y+y2