已知α、β都是锐角,sinα=4⼀5,cos(α+β)=5⼀13,求sinβ

2025-03-26 02:16:08
推荐回答(3个)
回答1:

因为α、β都是锐角,sinα=4/5 cos(α+β)=5/13
则:cosα=(1-sinα)^1/2=3/5 sin(α+β)=12/13
所以:sinβ=sin(α+β-α)=sin(α+β)cosα-cos(α+β)sinα=16/65

回答2:

cosa=3/5,sin(a+b)=12/13

sinb
=sin((a+b)-a)
=sin(a+b)cosa-sinacos(a+b)
=12/13×3/5-4/5×5/13
=36/65-20/65
=16/65

回答3:

则cosα=3/5,sin(α+β)=12/13
sinβ=sin(α+β-α)=sin(α+β)cosα-cos(α+β)sinα=12/13×3/5-5/13×4/5=16/65