(1) Na2SO3 + H2O <==> NaHSO3 + NaOH
(2)[HSO3-][OH-]/[SO32-] ==[HSO3-][OH-][H+]/[SO32-][H+]== Kw/ka(2)
(3)[OH-] =={Kw*0.01/Ka(2)}^1/2
Kb1=Kw/Ka2=10^-14/(6.6*10^-8)=1.51*10^-7
POH=1/2(PKb1+Pc)=1/2(P1.51*10^-7+P0.01)=4.41
PH=14-4.41=9.59
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