解方程-2x^3+3x^2-1=0怎么解

解方程-2x^3+3x^2-1=0怎么解
2024-11-30 14:32:09
推荐回答(3个)
回答1:

-2x^3+3x^2-1=0
(-3x^3+3x^2)+(x^3-1)=0
-3x^2(x-1)+(x-1)(x^2+x+1)=0
(x-1)(-2x^2+x+1)=0
(x-1)(-2x-1)(x-1)=0
所以x=1或者x=-1/2
希望采纳!

回答2:

-2x^3+3x^2-1=0

-2x^2(x-1)+x^2-1=0

-2x^2(x-1)+(x-1)(x+1)=0
(x-1)(-2x^2+x+1)=0
x=1
-2x^2+x+1)=0

x=1.x=-1/2

回答3:

-2x^3+3x^2-1=0
2x^3-3x^2+1=0
2x^2(x-1)-(x^2-1)=0
2x^2(x-1)-(x+1)(x-1)=0
(x-1)(2x^2-x-1)=0
(x-1)(x-1)(2x+1)=0
(x-1)^2(2x+1)=0
(x-1)^2=0,x=1
2x+1=0,x=-1/2