解方程：1⼀(x-6)-1⼀(x-5)=1⼀(x-4)-1⼀(x-3)

解：1/(x-6)-1/(x-5)=1/(x-4)-1/(x-3)
(x-5-x+6)/(x-5)(x-6)=(x-3-x+4)/(x-3)(x-4)
1/(x-5)(x-6)=1/(x-3)(x-4)
(x-5)(x-6)=(x-3)(x-4)
x^2-7x+12=x^2-11x+30
解得：x=9/2
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x:1/4=4/5:10
解：10x=1/4*4/5
10x=1/5
x=1/50

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解：
1/(x-6)-1/(x-5)=1/(x-4)-1/(x-3)
[(x-5)-(x-6)]/[(x-6)(x-5)]=[(x-3)-(x-4)]/[(x-4)(x-3)]
(x-5-x+6)/[(x-6)(x-5)]=(x-3-x+4)/[(x-4)(x-3)]
1/[(x-6)(x-5)]=1/[(x-4)(x-3)]
(x-6)(x-5)=(x-4)(x-3)
x²-11x+30=x²-7x+12
-11x+7x=12-30
-4x=-18
x=18/4
x=9/2