计算(2倍根号3+3倍根号2-根号6)(2倍根号3-3倍根号2-根号6)

2024-10-30 22:04:23
推荐回答(1个)
回答1:

(2√3+3√2-√6)(2√3-3√2-√6)
=[(2√3-√6)+3√2] [(2√3-√6)-3√2]
=(2√3-√6)²-(3√2)²
=12-12√2+6-18
=-12√2
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