请教一篇文章翻译

2025-04-01 18:07:41
推荐回答(1个)
回答1:

几乎所有的RNA的处理和DNA酶处理表明,选择性为骨干,组成相应的序列或其核酸酸基板。这个底物选择性,尤其是至关重要的艾滋病毒- 1逆转录酶(逆转录) ,其中具有约束力和歧视之间的各种核酸酸复式为独特的催化功能。逆转录是一个杂二聚体构成的一p51和p66亚基,后者其中载有积极的催化DNA聚合酶和核糖核酸酶H域,促进一个复杂的,多步反应转换为单滞留的RNA基因组到双滞留的DNA 。第一,利用反转录病毒RNA基因组作为一个模板和东道国细胞转移的RNA作为引物合成负链DNA , RNA的生产一- DNA的杂交。这全双工成为衬底的核糖核酸酶H域的RT , cleaves RNA的钢绞线在无数点,留下短的RNA片段杂交新生dna8 - 10 。其中这些RNA ,两个具体的嘌呤丰富的序列,称为该polypurine域( ppts ) ,作为独特的引物开始合成加链DNA ,从而创造双滞留的DNA病毒基因组中。具体卵裂由核糖核酸酶H然后删除的PPT引物和暴露了一体化的序列,以方便插入病毒DNA导入东道国chromosome14 。不适当的启动合成的加链DNA在其他RNA的环节,防止integration.rt ,因此必须遵守下列引物选择规则:第一, DNA引物容易进行聚合酶活性的逆转录;第二,通用RNA的引物是不是有效地延长逆转录但容易从事核糖核酸酶H活性的反转录时,退火与DNA ;第三,的PPT的RNA可以直接均DNA聚合酶活性及网站的具体核糖核酸酶H活性的RT 。机制,其中的RT之间的歧视,这些基板,并执行适当的催化功能,但了解甚少。虽然核糖核酸酶H卵裂的分析表明,存在不同的互动模式的RT与基板,晶体结构至今已显示,只有一个酶具有约束力的方向“ 。

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