java,以递归方式计算1!+2!+3!+...+10!的和

java,以递归方式计算1!+2!+3!+...+10!的和
2024-12-03 06:12:24
推荐回答(4个)
回答1:

/**
 * 计算阶乘
 * @param i 要计算的数
 * @return 阶乘结果
 */
public static long count(long i) {
// 如果当前值是1, 则返回1
if(i == 1)
return 1;

// 得到当前数的阶乘 + 当前数的下个数的阶乘
return i*count(i-1) + count(i-1);
}


希望能帮助你

回答2:

public class Digui {
public static void main(String[] args) {
int sum = 0;
for(int i=1;i<=10;i++)
{
sum+=jiecheng(i);
}
System.err.println(sum);
}
public static int jiecheng(int i)
{

if(i>1)
return i*jiecheng(i-1);
else
return 1;
}
}

回答3:

public int add(int start, int end){
if (start < end) {
return (start + add(++start, end));
}
return start;
}

回答4:

public class D {

public int digui(int n){
if(n==1){
return 1;
}else{
return digui(n-1)+n;
}

}
public static void main(String[] args) {
D d=new D ();
System.out.println(d.digui(10));

}

}

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