推荐回答(1个)
这个残局,你提了两次啊,正好换另外一种方法
用异数对配合矩形删减法可以解决问题:
【“异数对”化解法:】
同行、同列或同宫中某两格都只有2个数且其中有1个数是相同的,称为A,那么就可以删除该行、该列或该宫中与A相同的数。
且同行、同列或同宫中某两格同时可以存在几对异数对,两数相同的异数对优先于只有1个数相同的异数对,【称AB对】注意后面不能删减的例子分析。
![](/picurl?url=https%3A%2F%2Fiknow-pic.cdn.bcebos.com%2F314e251f95cad1c820f4f87f7e3e6709c93d511e%3Fx-bce-process%3Dimage%252Fresize%252Cm_lfit%252Cw_600%252Ch_800%252Climit_1%252Fquality%252Cq_85%252Fformat%252Cf_auto)
蓝色方框内,删减掉红斜线的8,删掉这个8后
之后,立马就可以删减掉八行蓝色圆圈旁边的8了 【第九行的8引起】
左下九宫内,36,368,38,根据异数对,可以删减掉368中的3
红色圆圈里的,标蓝色记号的3可以删减掉
接下来,应用矩形顶点删减法
1. 当某个数字在某两列仅出现在相同的两行时,就可以把这两行其它宫格候选数中的该数字删减掉。
2. 同理,当某个数字在某两行仅出现在相同的两列时,就可以把这两列其它宫格候选数中的该数字删减掉。
![](/picurl?url=https%3A%2F%2Fiknow-pic.cdn.bcebos.com%2F50da81cb39dbb6fdf77ee57e0824ab18972b3744%3Fx-bce-process%3Dimage%252Fresize%252Cm_lfit%252Cw_600%252Ch_800%252Climit_1%252Fquality%252Cq_85%252Fformat%252Cf_auto)
上图应用矩形顶点,r1c2,r1c8,r8c2,r8c8四个顶点中的3,符合矩形顶点删减法,所以
删减掉r8c7 的3
![](/picurl?url=https%3A%2F%2Fiknow-pic.cdn.bcebos.com%2Fb17eca8065380cd7a59fa3b5a044ad34588281e0%3Fx-bce-process%3Dimage%252Fresize%252Cm_lfit%252Cw_600%252Ch_800%252Climit_1%252Fquality%252Cq_85%252Fformat%252Cf_auto)
应用矩形顶点,注意看矩形的四个顶点是6,删减掉r8c2的6
所以,r8c2 是 3
接下来就不用多说了,你懂的
呵呵,其实矩形顶点,用一下后面那个删减,就可以确定数字了,不过正好当例子举吧
你这个残局很好的,让我对那个异数对,还有矩形顶点的应用又加深了下印象
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