计算[log4(3)+log8(3)]*[log3(2)+log9(2)] 其实(3)是没有括号的,是否表达明白了?

2024-12-01 07:43:40
推荐回答(1个)
回答1:

log4(3)=(1/2)log2(3),log8(3)=(1/3)log2(3)
所以,log4(3)+log8(3)=(5/6)log2(3)
log9(2)=(1/2)log3(2)
所以,log3(2)+log9(2)=(3/2)log3(2)
所以,原式=[(5/6)log2(3)]*[(3/2)log3(2)]=(5/6)*(3/2)=5/4

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