这个很简单啊原式=1/8∫[1/(x-4)-1/(x+4)]dx=1/8[ln(x-4)-ln(x+4)]=C
∫dx/(x^-16)∫dx/(x+4)(x-4)∫dx(1/8(x-4)-1/8(x+4))=1/8∫dx/(x-4)-1/8∫dx/(x+4)=1/8( ln|x-4|-ln|x+4|)+C=ln|(x-4)/(x+4)| / 8+C
将X^2-16拆开
