x^2-(x⼀2)(x+1)+(x⼀3)(x-1)+(x⼀6)(x-2)

急求!!初二数学计算,
2024-12-03 06:43:58
推荐回答(4个)
回答1:

x^2-(x/2)(x+1)+(x/3)(x-1)+(x/6)(x-2)
=x²-1/2x²-1/2x+(1/3x²-1/3x)+(1/6x²-1/3x)
=1/2x²-1/2x+1/3x²-1/3x+1/6x²-1/3x
=x²-7/6x

回答2:

x^2-(x/2)(x+1)+(x/3)(x-1)+(x/6)(x-2)
=x²-x²/2-x/2+x²/3-x/3+x²/6-x/3
=x²-7x/6

回答3:

x^2-(x/2)(x+1)+(x/3)(x-1)+(x/6)(x-2)
=x^2-(3x/6)(x+1)-(2x/6)(x-1)-(x/6)(x-2)
=x^2-(x/6)[3(x+1)-2(x-1)-(x-2)]
=x^2-(x/6)(3x+3-2x+2-x+2)
=x^2-(x/6)*7
=x^2-7x/6

回答4:

=X^2-7X/6