【数学之美】团队为您解答,若有不懂请追问,如果解决问题请点下面的“选为满意答案”。
sin(2x)/(1+sin²x)
=sin(2x)/[1+(1-cos(2x))/2]
=2sin(2x)/[3-cos(2x)]
∫[sin2x/(1+sin²x)] dx
=∫2sin(2x)/[3-cos(2x)]dx
=∫1/[3-cos(2x)]d(-cos(2x))
=ln[3-cos(2x)] +C
∫sin2x/(1+sin^2x)dx
= ∫2sinxcosx/(1+sin^2x)dx
= ∫2sinxdsinx/(1+sin^2x)
= ∫dsin^2x/(1+sin^2x)
= ln(1+sin^2x) + c