求不定积分 ∫sin2x⼀(1+sin^2x)dx 求解!!

求不定积分 ∫sin2x/(1+sin^2x)dx 求解!! 谢谢
2024-11-08 13:43:27
推荐回答(3个)
回答1:

 

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回答2:

sin(2x)/(1+sin²x)
=sin(2x)/[1+(1-cos(2x))/2]
=2sin(2x)/[3-cos(2x)]

∫[sin2x/(1+sin²x)] dx
=∫2sin(2x)/[3-cos(2x)]dx
=∫1/[3-cos(2x)]d(-cos(2x))
=ln[3-cos(2x)] +C

回答3:

∫sin2x/(1+sin^2x)dx
= ∫2sinxcosx/(1+sin^2x)dx
= ∫2sinxdsinx/(1+sin^2x)
= ∫dsin^2x/(1+sin^2x)
= ln(1+sin^2x) + c