如图所示电路,电源电压保持不变.闭合开关S,当滑动变阻器滑片P从A端滑到B端时,电流表示数变化了0.2A,

2024-11-27 18:47:40
推荐回答(1个)
回答1:

1、电压V1示数从6V变到5V,电流表示数变化了0.2A,故R1=(6-5)/0.2=5欧
则原来的电流为I1=6/5=1.2A,后来的电流为I2=1.2-0.2=1A(或5/5=1A)
2、当滑动变阻器滑片P在A端时此时电阻应为零,电压表示数应为:0V,对应的电流为1.2A
当滑动变阻器滑片P在B端时此时,此时电压表示数应为3V(因为原来为0V,电压表V2的示  数变化了3V),对应的电流为1A,滑动变阻器的阻值Rt=3/1=3欧。
3、电压V1示数从6V变到5V,在R1的电压下降了1V,电压表V2的示数变化了3V(上升),
它们 俩总的是上升了(3-1)2V。由于电源电压保持不变,所以R3的电压下降了2V,因此R3=2/0.2=10欧
4、电源电压为:(10+5+3)*1=18V 或(10+5)*1.2=18V
5、总功率变化:18*1.2-18*1=3.6W或18*0.2=3.6W 或1.2*1.2*(10+5)-1*1(10+5+3)=3.6W

所以答案为:A、D

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