高一数学:已知x+x的-1次方=3,求下列各式的值:(1)x的二分之一次方+x的负二分之一次方;(2)x的平方

2025-01-20 15:40:44
推荐回答(5个)
回答1:

1、号打不出来 太麻烦 我就用 x(1/2) 来表示X的二分之一次方了 [ ]2 表示括号里面的平方
[x(1/2)+x(-1/2)]2=[x(1/2)]2+[x(-1/2)]2+2*x(1/2)*x(-1/2)=x+x(-1)+2=5 由已知可的X是正数 所以第一个答案是根号5
2、[x+x(-1)]2=x2+x(-2)+2*x2*x(-2)=x2+x(-2)+2=9 x2+x(-2)=7

回答2:

(1)x+x的-1次方=3
x+2+1/x=3+2
(√x+1/√x)²=5
∴√x+1/√x=√5
x的二分之一次方+x的负二分之一次方=√5

(2)x+x的-1次方=3
(x+1/x)²=9
x²+2+1/x²=9
∴x²+1/x²=7
x的平方+x的负2次方=7

回答3:

(1)根号x加上根号1/x
等于大根号下(根号x加上根号1/x)^2
等于大根号下(x+1/x+2)
等于大根号下(3+2)
等于根号5
(2)x^2+1/x^2
=(x+1/x)^2-2
=3^2-2
=9-2
=7

祝你开心
不懂再问,满意记得采纳哈

回答4:

(1)因为X+X-1(上标)=3所以(X1/2+X-1/2)2-2=3,所以X1/2+X-1/2=+-1(正负一);
(2)同上可得7

回答5:

(1 .)x^(1/2)+1/(x^(1/2))=2 ,(根号下x+根号下x分之一)^2-2=3 所以所求为2
(2)x的平方+x的平方分之一=(x+1/x)^2-2 又因为x+x分之一=3所以所求为7

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