m^2-3m-1=-3如何解?求详细过程,谢谢

2025-01-19 11:15:12
推荐回答(2个)
回答1:

m^2-3m+2=0 (m-1)(m-2)=0 m=1或者m=2

回答2:

解:m^2-2*(3/2)*m+(3/2)^2-9/4-1=-3
(m-3/2)^2=-3+1+9/4
(m-3/2)^2=1/4
所以m-3/2=1/2 或m-3/2=-1/2
则m=2或m=1