(1-1⼀2的2次方)(1-1⼀3的2次方)......(1-n的2次方)是多少啊啊啊啊啊,急急急急

2024-12-03 02:04:24
推荐回答(2个)
回答1:

(1-1/2的2次方)(1-1/3的2次方)......(1-n的2次方)
=(1-1/2)(X+1/2)(1-1/3)(1+1/3)...(1-1/N)(1+1/n)
=1/2x3/2x2/3x3/4x...x(n-1)/n (n+1)/n
=1/2x(n+1)/n
=(n+1)/2n

回答2:

看成平方差公式做,例1-1/2的平方=(1-1/2)(1+1/2)以此类推