化简,(X^2+2)^2-2(x+2)(x-2)(x^2+4)+(x^2-2)^2

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2025-03-31 00:41:42
推荐回答(1个)
回答1:

(x^2+2)^2-2(x+2)(x-2)(x^2+4)+(x^2-2)^2
=(x^2+2)^2-2(x^2-4)(x^2+4)+(x^2-2)^2
=x^4+4x^2+4-2(x^4-16)+x^4-4x^2+4
=2x^4+8-2(x^4-16)
=2x^4+8-2x^4+32
=40