求高手解答奥数问题 急用

2025-02-25 10:38:07
推荐回答(4个)
回答1:

1,设每排共有x个座位,前排有y排
则800/x排 后排共800/x-y排
前排收入为:xy*10=6x*(800/x-y)+1600
10xy=6*800-6xy+1600
16xy=4800+1600=6400
xy=400
总收入为10xy+10xy+1600=20*400+1600=8000+1600=9600
2,设乙有x元
则甲有2x元,丙有55-3x>10
3x<45
x<15
由于丙最少所以有
55-3x<=x
4x>=55
x>=13.75
13.75<=x<15
从而有x=14
甲有28元,乙有14元,丙有13元
没有考虑55-3x=10的情况。
若能等于的话,则x=15
三人的钱分别为30 15 10

回答2:

1.设前排x个座位,后排y个座位,于是
x+y=800
6y-10x=1600
解方差组,得x=200,y=600
于是,总收入为10x+6y=5600元

2. 设甲乙丙分别有x,y,z元钱,于是
x+y+z=55
x=2y
z=10 且z为正整数(这个很重要)
于是,
x=28,y=14,z=13或者
x=30y=15,z=10

回答3:

前排座位数设为x,后排数则为(1200-x)
前排收入10x,后排收入6(1200-x)
10x-6(1200-x)=5600

x=800

前排数800,后排数1200-800=400

回答4:

你不会也是塘下奥数学校的学生吧。。。
第一题答案是5600
前排2000元,一共200个位置
后排3600元,一共600个位置
解:设前排有x个座位,后排有(800-x)个
(800-x)×6-10x=1600
4800-16x =1600
16x=3200
x =200
前排200×10=2000后排(800-200)×6=3600 总计2000+3600=5600
验算3600-2000=1600
= =貌似上网查这是我提出来的意见,结果自己回答了。。。考试加油`(*∩_∩*)′

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