求支反力时,取梁整体为受力分析对象:
无须(且不能)将力偶转换为力
ΣMA =0, RB.L +Mc -qL.L/2 =0
RB.L +qL^2/4 -qL.L/2 =0
RB =qL/4(向上)
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ΣFy =0, RAy +RB -qL =0
RAy +qL/4 -qL =0
RAy = qL(3/4)(向上) ①
无X方向荷载,RAx =0
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验算RAy:
ΣMB =0, -RAy.L +Mc + +qL.L/2 =0
-RAy.L +qL^2/4 +qL.L/2 =0
RAy = qL(3/4)(向上) ,结果与①相同