用C++设计一个日历程序

2025-02-07 13:47:08

推荐回答（3个）

回答1：

#include
#include
#define SIGN_WEEK 6
#define SIGN_YEAR 2000
void calendar(int week,int year) //显示日历
{
int month_day[14]={31,31,0,31,30,31,30,31,31,30,31,30,31,31};
char month_name[12][10]={"January","February","March","Apirl","May","June","July","August","September","October","November","December"};
int i,j,n,m,num0=0,num1=31,nweek0=week,nweek1;
if(year%4==0)
{
if(year%100!=0) month_day[2]=29;
else
{
if(year%400==0) month_day[2]=29;
else month_day[2]=28;
}
}
else month_day[2]=28;
system("CLS");
printf("The calendar of the year %d\n\n",year);
for(m=0;m!=12;m+=2)
{
if(m-1<0)
{
nweek0=week;
nweek1=(week+num1%7)>7?(week+num1%7)-7:(week+num1%7);
}
else
{
num0=num0+month_day[m-1]+month_day[m];
nweek0=(week+num0%7)>7?(week+num0%7)-7:(week+num0%7);
num1=num1+month_day[m]+month_day[m+1];
nweek1=(week+num1%7)>7?(week+num1%7)-7:(week+num1%7);
}
printf("%-10s %2d %-10s %2d\n=========================== ===========================\nSun Mon Tue Wed Thu Fri Sat Sun Mon Tue Wed Thu Fri Sat\n",month_name[m],m+1,month_name[m+1],m+2);
for(i=nweek0,j=nweek1,n=0;j!=nweek1-6*7;j--)
{
if(n<7)
{
if(i>0) printf("%3d ",month_day[m]-i+1);
else if(i<=0)
{
if(i>-month_day[m+1]) printf("%3d ",-i+1);
else printf("%3d ",-i-month_day[m+1]+1);
}
i--;
j+=1;
n++;
}
else
{
if(j>0) printf("%3d ",month_day[m+1]-j+1);
else if(j<=0)
{
if(j>-month_day[m+2]) printf("%3d ",-j+1);
else printf("%3d ",-j-month_day[m+2]+1);
}
n++;
}
if(n==14)
{
printf("\n");
n=0;
}
}
printf("=========================== ===========================\n\n");
}

}
void startWeek(int year) //确定需要显示的年份的第一天是星期几
{
int start_week,days;
if(year>SIGN_YEAR)
{
days=(year-SIGN_YEAR)*365+(year-SIGN_YEAR)/4-(year-SIGN_YEAR)/100+(year-SIGN_YEAR)/400+(((year-SIGN_YEAR)%4)+3)/4+((year-SIGN_YEAR)%400==0?0:((year-SIGN_YEAR)%100==0?1:0));
start_week=(SIGN_WEEK+days%7)>7?(SIGN_WEEK+days%7)-7:(SIGN_WEEK+days%7);
}
else
{
days=(SIGN_YEAR-year)*365+(SIGN_YEAR-year)/4-(SIGN_YEAR-year)/100+(SIGN_YEAR-year)/400;
start_week=(SIGN_WEEK-days%7)>0?(SIGN_WEEK-days%7):(SIGN_WEEK-days%7+7);
}
calendar(start_week,year);
}
int main()
{
int year,i;
printf("1.Calendar\n2.Query\nSelect:");
scanf("%d",&i);
if(i==1)
{
printf("Enter year:");
scanf("%d",&year);
startWeek(year);
}
else
{
//function 2 code
}
getchar();
getchar();
return 0;
}

回答2：

一般是从1900年1月1号（星期一）开始算的，然后算出这个月的1号是星期几，在打印出这个月的月历，下面是计算星期几的代码参考下
#include

using namespace std;
enum Weekdays{Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday };
struct Date{
int year,month,day;
};

bool isleapyear(int y)
{ return ((y%4==0 && y%100!=0)||(y%400==0));}

Weekdays getweekday(Date &d)
{
unsigned int n=5;
Weekdays w;

for(int i=2000;i { if(isleapyear(i))
n+=366;
else
n+=365;

}

for(i=1;i { switch(i)
{ case 1:case 3:case 5:case 7:case 8: case 10:case 12:
n+=31; break;
case 4:case 6:case 9:case 11:
n+=30; break;
case 2:
if(isleapyear(i))
n+=29;
else
n+=28;

break;
}
}

n+=d.day;
w=Weekdays(n%7);
return w;
}

void printWeekdays(Weekdays w)
{

switch(w)
{ case 0: cout<<"Sunday\n";break;
case 1: cout<<"Monday\n";break;
case 2: cout<<"Tuesday\n";break;
case 3: cout<<"Wednesday\n";break;
case 4: cout<<"Thursday\n";break;
case 5: cout<<"Friday\n";break;
case 6: cout<<"Saturday\n";break;
}
}

void main()
{
Date d; Weekdays w;
cout<<"input date:"; cin>>d.year>>d.month>>d.day;
w=getweekday(d);
cout<<"the date week is:";
printWeekdays( w);

回答3：

调用函数错了

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