单片机高手请进,求单片机六位数码管显示程序,谢谢

六位数码管显示程序
2024-12-10 02:35:31
推荐回答(2个)
回答1:

这是我的测量信号频率和相位的部分程序,是八位显示的
自己参考一下
P00-P03接74LS48的ABCD ,P04接
数码管dp
P20-P22接74ls138ABC,138输出接数码管选通
#include//头文件//
#define uchar unsigned char
#define uint unsigned int
#define ulint unsigned long int
#define din P3
//全局变量定义
int dp=0;
uchar data dis_buf[8];//8位显示的数值
uchar Nx[4]={0x00,0x00,0x00,0x00};
uchar Ns[4]={0x00,0x00,0x00,0x00};
float na=565464;//测频率个数na/
float nb=65;//测频率个数nb/
float f,jf=0;//计算频率/
float x,jx=0;//计算相位/
float Fs=60000000;//时钟频率/
sbit clr=P2^7; //清零/
sbit key1=P1^0;//测相/
sbit key2=P1^1;//测频/
sbit led1=P1^2;//测相指示/
sbit led2=P1^3;//测频指示/
sbit SEL0=P1^5;
sbit SEL1=P1^6;
sbit SEL2=P1^7;
sbit ju=P1^4;
void display(void);//显示程序/
void readdata(void);//读数程序/
void zhuanh(ulint sf);//数据转换程序/
void frequ(void);//频率程序/
void frase(void);//相位程序
void delay(uchar s);//延时程序/
void keyb(void);

void main() //主程序/
{
IE=0x00;
P1=0x13;
while(1)
{
display();

keyb();

display();
}
}

void frequ() //频率测量计算/
{ ulint k;

if(na!=0)
{
f=Fs/(2*(na+nb));
if(f>=10000)
{dp=0;
jf=Fs/(2*(na+nb));
}
else if(f>=1000)
{dp=1;
jf=Fs/(2*(na+nb))*10;
}
else if(f>=100)
{dp=2;
jf=Fs/(2*(na+nb))*100;
}
else if(f>=10)
{dp=3;
jf=Fs/(2*(na+nb))*1000;
}
else
{dp=4;
jf=Fs/(2*(na+nb))*10000;
}
}
else
{f=0;
dp=1;
}
k=jf;

zhuanh(k);

display();
keyb();
}

void frase() //相位测量与计算/
{ ulint h;
float jjx=na/(2*(na+nb));
if(nb!=0)
{
x=jjx*360;
if(x>=10000)
{dp=0;
jx=jjx;
}
else if(x>=1000)
{dp=1;
jx=jjx*360*10;
}
else if(x>=100)
{dp=2;
jx=jjx*360*100;
}
else if(x>=10)
{dp=3;
jx=jjx*360*1000;
}
else if(x>=1)
{dp=4;
jx=jjx*360*10000;
}
if(ju==0) //超前滞后判断..超前加上180度/
jx=jx+18000;
}
else
{
jx=18000;
dp=2;
}
h=jx;
zhuanh(h);
display();
keyb();
}

void zhuanh(ulint sf) //数据转换处理/
{
int i=0;
int j=4;
ulint f;
uchar data deal_data[5];
for(f=sf;f>=10;)
{deal_data[i]=f%10;
f=f/10;
i++;
}
deal_data[i]=f;
i++;
for(;i<5;i++)
{
deal_data[i]=0;
}
i=4;
j=5;
while(j)
{j--;
dis_buf[5-i]=deal_data[i];
i--;
}

//while(j)
//{j--;
//dis_buf[j]=0;

// }

dis_buf[5-dp]=dis_buf[5-dp]|0x10;
}
//延时程序//
void delay(uchar s)
{
uchar l;
for(l=0;l<=s;l++);
}

//显示程序/
void display(void)
{

int i=0;
int j=5;
int a=2;
if(ju==0)
dis_buf[0]=0x0a;
else dis_buf[0]=0xff;
for(j=0;j<6;j++)
{
P2=a;
P0=dis_buf[j];
a++;
delay(100);
}
}

//读数子程序/
void readdata(void)
{
unsigned long data m[2]={0x00000000,0x00000000};

SEL0=0;
SEL1=0;
SEL2=0;
Nx[0]=din;
SEL0=1;
Nx[1]=din;
SEL1=1;
Nx[3]=din;
SEL0=0;
Nx[2]=din;
SEL0=0;
SEL1=0;
SEL2=1;
Ns[0]=din;
SEL0=1;
Ns[1]=din;
SEL1=1;
Ns[3]=din;
SEL0=0;
Ns[2]=din;

m[0]=m[0]|Nx[0];
m[0]=m[0]<<8;
m[0]=m[0]|Nx[1];
m[0]=m[0]<<8;
m[0]=m[0]|Nx[2];
m[0]=m[0]<<8;
m[0]=m[0]|Nx[3];

m[1]=m[1]|Ns[0];
m[1]=m[1]<<8;
m[1]=m[1]|Ns[1];
m[1]=m[1]<<8;
m[1]=m[1]|Ns[2];
m[1]=m[1]<<8;
m[1]=m[1]|Ns[3];
na=m[0];
nb=m[1];

}

void keyb(void) //键盘/
{
bit s=!(key1&&key2);
while(s)
{if(key1==0)
{// delay1ms(10);/

clr=0;//开启CPLD /
clr=1;
led1=1;
led2=0;
//readdata();
frequ();//测频率/
}
else if(key2==0)
{//delay1ms(10);/

clr=0;//开启CPLD /
clr=1;
led1=0;
led2=1;
//readdata();
frase();//测相位/
}
}
}
//延时t=m*(nT+T)/
void delay1(uchar m,uchar n)
{

for(m=255;m>0;m--)
for(n=255;n>0;n--);
}

回答2:

一般这种是要给出原理图才行吧...

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