arctany=-arctanx+c 请问这个函数怎么化简?化成不带反正切符号的

2025-03-30 00:07:07
推荐回答(1个)
回答1:

arctany = -arctanx + C
tan( arctany ) = tan( -arctanx + C )
y = ( tan(-arctanx) + tanC ) / ( 1 - tan(-arctanx) * tanC )
= ( -x + tanC ) / ( 1 + x*tanC )