不定积分 ∫1⼀x(x^2+2)dx如何解

2024-12-02 03:24:08
推荐回答(1个)
回答1:

∫1/x(x^2+2)dx
=1/2*S1/xdx-1/2*S1/(x^2+2)dx
=1/2*ln|x|-1/2根2*S1/(x/根2)^2+1)d(x/根2)
=1/2*ln|x|-1/2根2*arctan(2根2)+c