子网掩码为255.255.255.192且IP地址为192.168.10.2主机属于哪个子网,怎么得出答案的

2024-11-23 04:46:50
推荐回答(5个)
回答1:

属于192. 168. 10. 0网络。计算步骤如下:

  1. 子网掩码255.255.255.192用二进制表示为: 11111111.11111111.11111111.11000000

  2. IP地址192.168.10.2用二进制表示为: 11000000.10101000.00001010.00000010

  3. 将二者“与”运算得: 11000000.10101000.00001010.00000000

  4. 转化成十进制表示就是 192. 168. 10. 0

扩展资料

1、利用子网数来计算

在求子网掩码之前必须先搞清楚要划分的子网数目,以及每个子网内的所需主机数目。

1)将子网数目转化为二进制来表示
2)取得该二进制的位数,为 N
3)取得该 IP地址的类子网掩码,将其主机地址部分的的前N位置 1 即得出该IP地址划分子网的子网掩码。

2、利用主机数来计算

1)将主机数目转化为二进制来表示

2)如果主机数小于或等于254(注意去掉保留的两个IP地址),则取得该主机的二进制位数。

3)将该类IP地址的主机地址位数全部置1,然后从后向前的将N位全部置为 0,即为子网掩码值。

参考资料:百度百科-子网掩码

回答2:

属于192.168.10.0/26这个子网。
子网掩码是255.255.255.192,就是说第4个八位是11000000,增值就是64,那么子网被划分为:
192.168.10.0/26;
192.168.10.64/26;
192.168.10.128/26;
192.168.10.192/26;
那么192.168.10.2就是第一个子网192.168.10.0/26中的主机地址。

我只是简略的说下,子网划分这里有点复杂,建议你去看一下相关书籍。

回答3:

子网掩码255.255.255.192用二进制表示为: 11111111.11111111.11111111.11000000
IP地址192.168.10.2用二进制表示为: 11000000.10101000.00001010.00000010

将二者“与”运算得: 11000000.10101000.00001010.00000000

转化成十进制表示就是 192. 168. 10. 0

这就是这个主机的网络地址

回答4:

192.168.10.0的网段,子网掩码转换成二进制是11111111,11111111,11111111,11000000.和IP地址做与运算得出192.168.10.0

回答5:

属于10的那个

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