(x√x+x√y)/(xy-y^2)-(x+√xy+y)/(x√x-y√y)
=x(√x+√y)/y(x-y)-(x+√xy+y)(x√x+y√y)/(x√x-y√y)(x√x+y√y)
=x(√x+√y)/y(x-y)-(x^2+xy+y^2)(√x+√y)/(x^3-y^3)
=x(√x+√y)/y(x-y)-(x^2+xy+y^2)(√x+√y)/(x-y)(x^2+xy+y^2)
=x(√x+√y)/y(x-y)-(√x+√y)/(x-y)
=[x(√x+√y)-y(√x+√y)]/y(x-y)
=(x-y)(√x+√y)/y(x-y)
=(√x+√y)/y
这已经是最简形式了
设 原式= ① - ②
① = x(√x-√y) / (y(x-y)) = ( x / y) * (1/(√x-√y) )
② = (x+√x *√y +y) / ( (√x)^3 - (√y)^3) = 1/(√x-√y)
原式= （x/y-1) * 1/(√x-√y)
= (√x +√y) / y
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