二分法的时间复杂度为O(log2n)是什么意思?

2025-04-06 17:57:14
推荐回答(3个)
回答1:

二分法的基本思想如下:
假设数据是按升序排序的,对于给定值x,从序列的中间位置开始比较,如果当前位置值等于x,则查找成功;若x小于当前位置值,则在数列的前半段中查找;若x大于当前位置值则在数列的后半段中继续查找,直到找到为止。
由于是数组是预先排序好的,所以可以采用折半查询的方式,每次抛掉待查询部分的一半
这样,长度为N的数组,只需要log2N次查询即可,2是对数的底。
例如,长度为7的数组,最多只需要3次就可以找到
O(log2n)只是表示是log2N同一数量级,因为有个取整的问题,而且也有可能在查询过程中就已经找到(也就是某个折半查询点正好是待查询数据),这样O(log2n)就是一个上限

回答2:

看数据结构或者算法导论去。。。

回答3:

我也不清楚

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