(ab)'=a'b+ab'f(x)=(x+1)²(x-1)³f'(x)=2(x+1)(x-1)³+(x+1)²3(x-1)²f'(x)=(x+1)(x-1)²[2(x-1)+3(x+1)]f'(x)=(x+1)(x-1)²(5x+1)
f`(x)=2(x+1)(x-1)^3+(x+1)^2 3(x-1)^2 =(x+1)(x-1)^2{2x-2+3x+3} =(x+1)(x-1)^2(5x+1)