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几何问题

2025-03-25 12:54:51

推荐回答（1个）

回答1：

因为是平移，可以证明，四边形ABFE是平行四边形，又因为AB=AC=EF=EA，所以四边形是菱形，所以四边形面积=2三角形面积=6，1 扫过的面积=6 2 AF垂直于BE 3 三角形为等边三角形，所以AC=2倍根号3的4次方（这里写不清楚，你解一下等边三角形就可以了）

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