两个自然数的和是126，最大公约数是180，这样的数有哪几组？
推荐回答（4个）
180=2*2*3*3*5
而和为126，则为两个偶数，或两个奇数。因为有2，所以只能有两个偶数。所以有5的必然有2。所以必然有一个数是10的倍数。126 可拆分为
a.10 116
b. 20 106
c. 30 96
d. 40 86
e. 50 76
f. 60 66
g. 70 56
h. 80 46
i. 90 36
j. 100 26
k. 110 16
l. 120 6
显然，符合条件有c.,l.。共两组。
两自然数必然为18的倍数,126以内18的倍数有18 36 54 72 90 108 126,而其中两数之和为126的为54和72,36和90,18和108,仅此三组.
18a + 18b = 126 , a,b互质
a+b = 7
a=1, b=6, 18, 108
a=2, b=5, 36, 90
a=3, b=4, 54, 72
有这种数字吗,你说的是不是最小公倍数啊
18 ,108
36,90
54,72
就他们了
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