推荐回答（3个）
像这样只有两个数字不正确的情况，是无法再解了。数学上已经证明了，这种情况下无解的。也就是说，如果把11和12两个数字的顺序搞对了，必然有其它两个数字的顺序不正确的。
输出只有一行。如果移动序列产生棋子重叠或棋子越界的错误，则输出wrong，否则，如果移动序列可以在给定的步数内将“caocao”移到出口位置(1, 0)，则输出yes，否则输出no。
Sample Input
caocao (2, 1, 2, 2)
zhangfei (0, 4, 2, 1)
guanyu (2, 4, 2, 1)
huangzhong (0, 3, 2, 1)
machao (2, 3, 2, 1)
zhaoyun (0, 2, 2, 1)
bing1 (0, 1, 1, 1)
bing2 (1, 1, 1, 1)
bing3 (0, 0, 1, 1)
bing4 (1, 0, 1, 1)
10
caocao v
zhaoyun ->
zhaoyun ->
bing2 ^
bing2 <-
bing4 ^
bing4 ^
caocao <-
Sample Output
yes
Hint
输出只有一行，在答案后面不要跟换行符。
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