解:(1)a²+b²-ab=c²a²+b²-c²=ab由余弦定理得:cosC=(a²+b²-c²)/(2ab)=ab/(2ab)=½C为三角形内角,C=π/3(2)C=π/3,ab=4S△ABC=½absinC=½·4·sin(π/3)=2·(√3/2)=√3