碱和盐反应化学方程式,求10个

2025-02-15 00:35:55
推荐回答(2个)
回答1:


+

--------
另一种碱
+
另一种盐
氢氧化钠与硫酸铜:2NaOH+CuSO4==Cu(OH)2↓+Na2SO4
氢氧化钠与氯化铜:2NaOH+CuCl2==Cu(OH)2↓+2NaCl
氢氧化钠与硝酸铜:2NaOH+Cu(NO3)2==Cu(OH)2↓+2NaNO3
氢氧化钾与硫酸铜:2KOH+CuSO4==Cu(OH)2↓+K2SO4
氢氧化钾与氯化铜:2KOH+CuCl2==Cu(OH)2↓+2KCl
氢氧化钾与硝酸铜:2KOH+Cu(NO3)2==Cu(OH)2↓+2KNO3
氢氧化钠与氯化铁:3NaOH+FeCl3==Fe(OH)3↓+3NaCl
氢氧化钠与氯化镁:2NaOH+MgCl2==Mg(OH)2↓+2NaCl
氢氧化钾与氯化铁:3KOH+FeCl3==Fe(OH)3↓+3KCl
氢氧化钾与氯化镁:2KOH+MgCl2==Mg(OH)2↓+2KCl
氢氧化钙与碳酸钠:Ca(OH)2+Na2CO3==CaCO3↓+2NaOH
氢氧化钙与碳酸钾:Ca(OH)2+K2CO3==CaCO3↓+2KOH

回答2:

1.可与可溶性碱(钾钠氨钡)生成碱沉淀的(oh沉淀的)
像fe
cu
mg
al
ca

这样的有
盐酸盐
硝酸盐
和除ca以外的硫酸盐
naoh
的可以写出
14种
koh
的可以写出
14种
氨水
的可以写出
14种
2.可与可溶性碱(钾钠氨钡)生成盐沉淀的沉淀的
ba(oh)和硫酸盐反应
可以写出
至少6个
硫酸盐的阳离子(k
na
nh3
fe
cu
mg
al

ba(oh)和碳酸盐反应
可以写出3个
ba(oh)和碳酸氢盐反应
可以至少写出3个

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