(1)∵
<
36
<
37
,
49
设
=6+k(0<k<1),∴(
37
)2=(6+k)2,
37
∴37=36+12k+k2,
∴37≈36+12k.
解得k≈
,1 12
∴
≈6+
37
≈6+0.08=6.08;1 12
(2)设
=a+k(0<k<1),
m
∴m=a2+2ak+k2≈a2+2ak,
∵m=a2+b,
∴a2+2ak=a2+b,
解得k=
,b 2a
∴