已知a+b=-6,ab=8试求根号b⼀a+根号a⼀b的值

2025-03-31 09:27:22
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回答1:


a+b=-6<0
ab=8>0
∴a<0,b<0
∴√b/a+√a/b
=√b²/ab+√a²/ab
=-b/√ab-a/√ab
=-(a+b)/√ab
=-(-6)/√8
=6/2√2
=3√2/2