python如何去除字符串中不想要的字符

2025-03-15 03:25:22
推荐回答(1个)
回答1:

问题:
过滤用户输入中前后多余的空白字符
‘ ++++abc123--- ‘
过滤某windows下编辑文本中的’\r’:
‘hello world \r\n’
去掉文本中unicode组合字符,音调
"Zhào Qián Sūn Lǐ Zhōu Wú Zhèng Wáng"
如何解决以上问题?
去掉两端字符串: strip(), rstrip(),lstrip()

123456789101112131415

#!/usr/bin/python3 s = ' -----abc123++++ ' # 删除两边空字符print(s.strip()) # 删除左边空字符print(s.rstrip()) # 删除右边空字符print(s.lstrip()) # 删除两边 - + 和空字符print(s.strip().strip('-+'))

删除单个固定位置字符: 切片 + 拼接

123456

#!/usr/bin/python3 s = 'abc:123'# 字符串拼接方式去除冒号new_s = s[:3] + s[4:]print(new_s)

删除任意位置字符同时删除多种不同字符:replace(), re.sub()

1234567891011

#!/usr/bin/python3 # 去除字符串中相同的字符s = '\tabc\t123\tisk'print(s.replace('\t', '')) import re# 去除\r\n\t字符s = '\r\nabc\t123\nxyz'print(re.sub('[\r\n\t]', '', s))

同时删除多种不同字符:translate() py3中为str.maketrans()做映射

1234567

#!/usr/bin/python3 s = 'abc123xyz'# a _> x, b_> y, c_> z,字符映射加密print(str.maketrans('abcxyz', 'xyzabc'))# translate把其转换成字符串print(s.translate(str.maketrans('abcxyz', 'xyzabc')))

去掉unicode字符中音调

12345678910111213141516171819202122232425
#!/usr/bin/python3 import sysimport unicodedatas = "Zhào Qián Sūn Lǐ Zhōu Wú Zhèng Wáng"remap = { # ord返回ascii值 ord('\t'): '', ord('\f'): '', ord('\r'): None }# 去除\t, \f, \ra = s.translate(remap)'''  通过使用dict.fromkeys() 方法构造一个字典,每个Unicode 和音符作为键,对于的值全部为None  然后使用unicodedata.normalize() 将原始输入标准化为分解形式字符  sys.maxunicode : 给出最大Unicode代码点的值的整数,即1114111(十六进制的0x10FFFF)。  unicodedata.combining:将分配给字符chr的规范组合类作为整数返回。 如果未定义组合类,则返回0。'''cmb_chrs = dict.fromkeys(c for c in range(sys.maxunicode) if unicodedata.combining(chr(c))) #此部分建议拆分开来理解b = unicodedata.normalize('NFD', a)'''   调用translate 函数删除所有重音符'''print(b.translate(cmb_chrs))

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