求解高数问题,画红线的这三步是什么意思,是怎么转换的的

2025-03-26 01:08:01
推荐回答(4个)
回答1:

导数定义

回答2:

左处:... = (1/2) ∫ <0, 1> dx [(2/3)(1-x^2+y^2)^(3/2)]<0, x>
= (1/3) ∫ <0, 1> [1-(1-x^2)^(3/2)]dx = ...
右处:... = ∫<1, 2>dy∫ (2y/π)sin[πx/(2y)]d[πx/(2y)]
= (2/π)∫<1, 2>ydy[-cos(πx/2y)]
= (2/π)∫<1, 2>y[cos(π/2)-cos(πy/2)]dy
= (-2/π)∫<1, 2>ycos(πy/2)dy = ...

回答3:

看一下你的题目😮

回答4:

不就是洛必达法则吗,对分子分母同时求导