1/(1+cost)的原函数是啥

2025-04-15 09:23:25
推荐回答(2个)
回答1:

∫1/(1+cost)dt
= ∫(1-cost)/sin^2 tdt
= ∫1/sin^2 tdt-∫d(sint)/sin^2 t
= 1/sint+cot t + C
= csc t + cot t + C

回答2:

tan(t/2)+c