令p=y'则y"=pdp/dy代入方程： pdp/dy+2/(1-y)*p^2=0dp/p=2dy/(y-1)积分： ln|p|=2ln|y-1|+C得：p=C1(y-1)^2dy/(y-1)^2=C1dx积分;-1/(y-1)=C1x+C2故y=1-1/(C1x+C2)
